lab_EE1C1_2_osciloscope_2025-09-11

📝Assignment

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🎯Learning objectives

1. Explain measurements using Ohm’s law, equivalent resistance, and Kirchhoff’s laws,
2. Explain the influence of non ideal meter impedance.
3. Use an oscilloscope,
4. Use a function generator,
5. Explain the influence of non ideal source resistance and frequency behavior,
6. Explain the need of a common ground

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✏️ Execises

3.1

3: $4.965\text{V}$, (5-4.965)/5*100%=0.7% 4: The multimeter is a paralel connection to the 1M$\Omega$ resistor, so $R_{eq}$ changes so the current ($I_{DC}$) changes which changes the value of the 1 $1M\Omega$

3.2

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2. $\sum i=0$ , $54.64\text{mA}\approx 49.32\text{mA}+5.15\text{mA}+0.53\text{mA}$

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2. $\sum V$ across a linear circuit is the total voltage
   1. it all adds up to 5V

3.4

1. 1. defining Ri cna be hard, because the amperage and voltage changes, and a short circuit is not possible,
   2. you have to take them into account when calculating Eeq
2. $i=\frac{U}{R}=\frac{u(t)}{R_i}$
3. 1. measure the current with 1 known resistor in loop
   2. measure the current with a different known resistor (getter a better accuracy to use a lower resistance, because it will be closer to the function generators resistance)
   3. solve for $R_i$
4. $i=\frac{U}{R}$
   1. $i_1=\frac{V}{100\Omega +R_i}=4.67\text{mA}$
   2. $i_2=\frac{V}{1000\Omega +R_i}=0.70\text{mA}$
   3. $V=4.67\text{mA}(100\Omega +R_i)$
   4. $\frac{4.67\text{mA}(100\Omega +R_i)}{1000\Omega +R_i}=0.7\text{mA}$
   5. $4.67\text{mA}(100\Omega +R_i)=0.7\text{mA}(1000\Omega +R_i)$
   6. $467\text{mA}\Omega +4.67\text{mA}{R}_i=700\text{mA}\Omega +0.7\text{mA}{R}_i$
   7. $3,97\text{mA}{R}_i=233\text{mA}\Omega$
   8. $R_i=58,69\Omega$

3.4

4. see measurements
   1. $f=10.0005Hz$ klopt
   2. $A=1.06\text{V}$ klopt
   3. $P=0.1s$ klopt
5. .
6. .
7. difference
   1. oscilloscope: 362mV
   2. digital multimeter: 357mV
   3. difference: 5mV $\approx 1.4\%$
8. it defines where the function passes through the y axis, the amplitude only multiplies the height of the funciton but not the location at which it passes through the y-axis
9. it moves the function diagonally up to the right