🏠 Homework


✏️ Execises

4.1

  1. protect system
    1. D1: They make sur that the current flows from the 15V to the ground (polarity)
    2. D0: makes sure that there is a stable voltage
  2. 4.1V
  3. 15/2200 = 0.01A

4.2

4.5

  • C1:100 πœ‡F βœ… 2025-10-09
  • C2: 10 πœ‡F βœ… 2025-10-09
  • D1, D2: 1N4148 βœ… 2025-10-09
  • IC1: LM4040-4.1 βœ… 2025-10-09
  • IC2: TL072 βœ… 2025-10-09
  • R1: 2.2 kΞ© βœ… 2025-10-09
  • R2: 2.7 kΞ© βœ… 2025-10-09
  • R3: 3.6 kΞ© βœ… 2025-10-09
  • R4: 18 kΞ© βœ… 2025-10-09
  • R5, R6: 15 kΞ© βœ… 2025-10-09 and furthermore:
  • +15V, -15V, GND (2Γ—), SIG GEN, OUT, INV OUT: 2-pin header βœ… 2025-10-09
  • INPUT SEL: 3-pin header βœ… 2025-10-09
  • jumper cap βœ… 2025-10-09
  • 3.5 mm jack socket βœ… 2025-10-09
  • DIL8 socket βœ… 2025-10-09

6.2

  1. 15V
  2. 0.681V lower
  3. opamp
    1. -15V is connected to the Vcc- pin through diode d2
    2. 15V is connected to the Non-inverting input A through D1, R1, R2, input(1β†’2)
    3. output A is connected to the out through C1
    4. Vcc+ is not connected
  4. opamp
    1. Vcc-=-14.78V
    2. InvA input=4.11V
    3. NonInvA input=-0.525V
    4. Output A = -0.5V
    5. Vcc+=14.78V
    6. Output B=-0.471
    7. inverted input B= -0.471
    8. non-inverting input B= 0V
  5. 10.2V/2.2k =4.5mA

6.3

  1. Yes 6V peak to peak
  2. yes
  3. The peak to peak decreases
  4. connecting the oscilloscpe to the inverting and ground outputs and then the peak to peak should be also 6V, use channel 1 and two and check the polarity to be the inverse of eachother

πŸ“„Assignment